JavaScript array_uintersect_assoc function

A JavaScript equivalent of PHP’s array_uintersect_assoc
[JS]function array_uintersect_assoc (arr1) {
  // http://kevin.vanzonneveld.net
  // +   original by: Brett Zamir (http://brett-zamir.me)
  // *     example 1: $array1 = {a: 'green', b: 'brown', c: 'blue', 0: 'red'}
  // *     example 1: $array2 = {a: 'GREEN', B: 'brown', 0: 'yellow', 1: 'red'}
  // *     example 1: array_uintersect_assoc($array1, $array2, function (f_string1, f_string2){var string1 = (f_string1+'').toLowerCase(); var string2 = (f_string2+'').toLowerCase(); if (string1 > string2) return 1; if (string1 == string2) return 0; return -1;});
  // *     returns 1: {a: 'green', b: 'brown'}
  var retArr = {},
    arglm1 = arguments.length - 1,
    arglm2 = arglm1 - 2,
    cb = arguments[arglm1],
    k1 = '',
    i = 1,
    arr = {},
    k = '';

  cb = (typeof cb === 'string') ? this.window[cb] : (Object.prototype.toString.call(cb) === '[object Array]') ? this.window[cb[0]][cb[1]] : cb;

  arr1keys: for (k1 in arr1) {
    arrs: for (i = 1; i < arglm1; i++) {
      arr = arguments[i];
      for (k in arr) {
        if (k === k1 && cb(arr[k], arr1[k1]) === 0) {
          if (i === arglm2) {
            retArr[k1] = arr1[k1];
          }
          // If the innermost loop always leads at least once to an equal value, continue the loop until done
          continue arrs;
        }
      }
      // If it reaches here, it wasn't found in at least one array, so try next value
      continue arr1keys;
    }
  }

  return retArr;
}
[/JS]
Example 1
$array1 = {a: 'green', b: 'brown', c: 'blue', 0: 'red'}
$array2 = {a: 'GREEN', B: 'brown', 0: 'yellow', 1: 'red'}
array_uintersect_assoc($array1, $array2, function (f_string1, f_string2){var string1 = (f_string1+'').toLowerCase(); var string2 = (f_string2+'').toLowerCase(); if (string1 > string2) return 1; if (string1 == string2) return 0; return -1;});

Should return
{a: 'green', b: 'brown'}
Теги:
array_uintersect_assoc
Добавлено: 21 Июля 2018 12:33:37 Добавил: Андрей Ковальчук Нравится 0
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